Shear, moment, slope and deflection of a beam that also carries an axial load — compression magnifies bending, tension reduces it; ends held against axial motion also covered
When a beam also carries a force along its axis, that force acts on the already bent beam and adds a moment P\cdot y. The governing equation gets one more term:
EI\,y'''' \pm P\,y'' = w(x)
With k = \sqrt{P/EI} the solution is built from \cos kx,\ \sin kx (compression) or \cosh kx,\ \sinh kx (tension). The calculator solves it in closed form for six load types and six end restraints, like the straight-beam calculator.
Every result is compared with the same beam and loads without the axial load. The ratios C_y and C_M tell you how much the axial force changes the maximum deflection and moment.
Each transverse load carries the full axial load — the axial force is not shared between them. With that rule the results for several loads can be added, and the calculator does exactly this.
If both ends are held so that the beam cannot shorten, bending stretches the centre line and creates a tension P by itself. In this mode P is a result: it is found from a cubic equation based on a one-term sine shape, and then the exact tension solution gives the moments. Two cases for a perfectly flexible cable are included as well.
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